(4x^2-9)/(2x^2-3x)

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Solution for (4x^2-9)/(2x^2-3x) equation:


D( x )

2*x^2-(3*x) = 0

2*x^2-(3*x) = 0

2*x^2-(3*x) = 0

2*x^2-3*x = 0

2*x^2-3*x = 0

DELTA = (-3)^2-(0*2*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)+3)/(2*2) or x = (3-9^(1/2))/(2*2)

x = 3/2 or x = 0

x in (-oo:0) U (0:3/2) U (3/2:+oo)

(4*x^2-9)/(2*x^2-(3*x)) = 0

(4*x^2-9)/(2*x^2-3*x) = 0

2*x^2-3*x = 0

x*(2*x-3) = 0

2*x-3 = 0 // + 3

2*x = 3 // : 2

x = 3/2

x*(x-3/2) = 0

(4*x^2-9)/(x*(x-3/2)) = 0

4*x^2 = 9 // : 4

x^2 = 9/4

x^2 = 9/4 // ^ 1/2

abs(x) = 3/2

x = 3/2 or x = -3/2

x in { 3/2}

x = -3/2

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